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Is there a dnf or yum command to show the size or number of applications available by default for Fedora and Centos?

asked 2016-09-15 06:01:36 -0500

Ervin-Reloaded gravatar image

I read that there is such a command in Debian showing that around 37 k packages are available. I found it somewhere online but I forgot where. Is there any similar terminal command in fedora with dnf or yum in centos? Since this command would be very useful in Centos also since it has a more limited number of packages than Fedora.

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Out of curiosity, why would that information be important? :-) I mean, if you need some application that is not available you can always install it from additional repositories like EPEL, RPMFusion or use COPR. You can even compile applications yourself ;-)

masteroman gravatar imagemasteroman ( 2016-09-15 10:54:36 -0500 )edit
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Hello Masteroman, it is merely for curiosity and study purposes, not for searching applications. Its' good to know for example how many packages are available in Centos vs how many packages are available in Fedora. And I am aware I can compile applications myself if I know how. If you do know how, please have a look at one of my questions in regards to Linphone. The question is about building from source, I would appreciate it if you could help with it.

Ervin-Reloaded gravatar imageErvin-Reloaded ( 2016-09-16 03:57:57 -0500 )edit

Already looked for it and replied to that question, unfortunately I don't have solution :-(

masteroman gravatar imagemasteroman ( 2016-09-16 06:26:32 -0500 )edit

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answered 2016-09-15 11:09:22 -0500

ptrck4193 gravatar image

Did not see such an item in the manual. Maybe this helps:

dnf -v repolist # Detailed list of repositories

Look for

Repo-id : fedora

Repo-pkgs : 38,811

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It worked like charm.

Ervin-Reloaded gravatar imageErvin-Reloaded ( 2016-09-16 03:56:50 -0500 )edit

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Asked: 2016-09-15 06:01:36 -0500

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Last updated: Sep 15 '16